比较基础的链表题,精髓在于使用dummy节点来方便的维护链表头。
public class Solution {
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
ListNode dummy = new ListNode(0);
ListNode temp = dummy;
while(l1 != null && l2 != null) {
if(l1.val < l2.val) {
temp.next = l1;
temp = temp.next;
l1 = l1.next;
}
else {
temp.next = l2;
temp = temp.next;
l2 = l2.next;
}
}
temp.next = l1 == null ? l2 : l1;
return dummy.next;
}
}
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